已知x+1⼀x=2倍根号2,求x-1⼀x的值

2025-05-14 02:03:20
推荐回答(2个)
回答1:

x+1/x=2√2 平方
x^2+2+1/x^2=8
x^2+1/x^2=6
x^2-2+1/x^2=6-2=4
(x-1/x)^2=4
x-1/x=±2

回答2:

(x+1/x)^2=8
两端-2,再配方。
(x-1/x)^2=6
开方即可。