若(a+3)²+|b-4|=0,求代数式(a+b)-(a-b)²的值

2025-05-18 04:52:15
推荐回答(2个)
回答1:

(a+3)²+|b-4|=0,
所以a+3=0,b-4=0,
a=-3,b=4

(a+b)-(a-b)²
=[(-3)+4)]-[(-3)-4]²
=1-(-7)²
=1-49
=-48

回答2:

(a+3)²+|b-4|=0,
a+3=0
b-4=0
a=-3,b=4

(a+b)-(a-b)²
=1-49
=-48