已知等差数列{a n }的首项a 1 =1,公差d>0.且a 2 ,a 5 ,a 14 分别是等比数列{b n }的b 1 ,b 2 ,b 3

2025-05-18 15:09:31
推荐回答(1个)
回答1:

(1)∵a 2 =1+d,a 5 =1+4d,a 14 =1+13d,且a 2 ,a 5 ,a 14 成等比数列,
∴(1+4d) 2 =(1+d)(1+13d),解得d=2,
∴a n =1+(n-1)?2=2n-1,
又b 1 =a 2 =3,b 2 =a 5 =9,
∴q=3, b n =3? 3 n-1 = 3 n
(2)
c 1
b 1
+
c 2
b 2
+…+
c n
b n
=a n+1 ,即
C 1
3
+
C 2
3 2
+…+
C n
3 n
=2n+1
①,
则n≥2时,
C 1
3
+
C 2
3 2
+…+
C n-1
3 n-1
=2n-1
②,
①-②得,
C n
3 n
=2
,所以 C n =2? 3 n (n≥2),
n=1时,C 1 =9,
所以 C n =
2? 3 n ,n≥2
9,n=1

所以c 1 +c 2 +…+c 2013 =9+2?3 2 +2?3 3 +…+2?3 2013
=9+2?
3 2 (1- 3 2012 )
1-3
=3 2014