∵在正方形ABCD中△PBC是等边三角形，∴PB=PC=BC，∴∠PBC=∠PCB=∠BPC=60°，∴∠PBA=∠DCP=30°，∴△APB≌△DPC，∴AP=DP，∵AB=BC=BP，∴∠PAB=∠APB=75°，∴∠APD=180°-2（90°-75°）=150°．故选D．
