f‘(x)=[(x－4)*³√(x＋1)]'
=(x－4)'*[³√(x＋1)]+(x－4)*[³√(x＋1)]'
=³√(x＋1)+(x－4)*[³√(x＋1)]'
=³√(x＋1)+(x－4)*(1/3)*(x+1)^(-2/3)
=......
f(x)=(x－4)׳√(x＋1)²
f(x)'=³√(x＋1)²+(x－4)*2/3*1/³√(x＋1)
=(x+1+2/3*(x-4))/³√(x＋1)
=(5/3x-5/3)/³√(x＋1)
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