解：将a(1,4)代入y=k2/x得k2=4,则反比例y=4/x令x=3，则y=4/3即m=4/3将a(1,4)b(3,4/3)代入y=k1x+b得,k1+b=43k1+b=4/3解得：k1=-4/3,b=16/3∴一次函数y=-4/3x+16/32）令y=0得：x=4∴C（4,0）则S△aob=S(AOC)-S(BOC)=(4*4)/2-(4*4/3)/2=16/3
