不等式组x^2-2X-3<=0 绝对值(x-a)<=2 (1当0<a<1时解不等式 (2)若不等式组解集为空集,求实数a取值范围

2025-05-17 20:53:11
推荐回答(1个)
回答1:

x^2-2X-3<=0 =>-1<=x<=3
|x-a|<=2 =>a-2<=x<=a+2
0a-2<-1 a+2<3
=>不等式组解集为 -1<=x<=a+2
如果a+2<-1 或者a-2>3,若不等式组解集为空集
=>a<-3或者a>5。