(x+3)/(x-5)=(m+2)/(x-5)(x+3)/(x-5)-(m+2)/(x-5)=0(x+1-m)/(x-5)=0去分母：x+1-m=0x=m-1要有增根，即要x=5那么m-1=5m=6有不懂欢迎追问
