f(x)=1/2sin2x+(1-cos2x)/2=1/2sin2x-1/2cos2x+1/2=√2/2(sin2x*√2/2-cos2x*√2/2)+1/2=√2/2sin(2x-π/4)+1/2最小正周期T=2π/2=π 2kπ-π/2<=2x-π/4<=2kπ+π/2kπ-π/8<=x<=kπ+3π/8单调递增区间 【kπ-π/8,kπ+3π/8】 k∈Z