lim x趋向于0 [ln(1+x)⼀x]^[1⼀(e^x-1)] 答案是e^-1⼀2求详细过程

2025-05-18 11:57:34
推荐回答(2个)
回答1:

原式=lim e^( ln[ln(1+x)/x] / (e^x-1))
=lim e^( ln[ln(1+x)/x] / x)
洛必达=lim e^[ (x-(1+x)ln(1+x)) / x(1+x)ln(1+x)]
=lim e^[ (x-(1+x)ln(1+x)) / (1+x)x²]
洛必达=lim e^[ -ln(1+x) /(3x²+2x)]

=lim e^[ -x /(3x²+2x)]
=lim e^[ -1 /(3x+2)]
=e^-1/2

回答2: