12+(13+23)+(14+24+34)+(15+25+35+45)+...+(1⼀100+...+99⼀100)=?求解答过程,急需解答!!

2025-05-17 06:59:30
推荐回答(1个)
回答1:

an=1/(n+1)+2/(n+1)+...+n/(n+1)
=(1+2+...+n)/(n+1)
=n(n+1)/2(n+1)
=n/2
∴原式=1/2+2/2+...99/2
=(1+2+...+99)/2
=(1+99)*99/2*2
=25*(100-1)
=2475