(x-2)(x+3)(x2+x-8)∵原式=(x-3)(x+4)(x-1)(x+2)+24=(x2+x-12)(x2+x-2)+24令x2+x=A,∴原式=(A-12)(A-2)+24=(A-6)(A-8)=(x2+x-6)(x2+x-8)=(x-2)(x+3)(x2+x-8)