解，体积乘以mol浓度得到物质的量再乘以分子量就是草酸的质量.0.1mol/L*.05L*126=0.6300g=630mg0mol酸与2mol碱中和.碱的量=0.1025*0.02305=0.00236酸的mol浓度=0.00236/2=0.00118mol/L.25ml中草酸的质量=0.025*0.00118*90.04=0.00277g=2.7736mg
