[x-2根号x+1]+[y-1-2根号（y-)+1]+[z-2-2根号(z-2)+1]=0化简得(根号x-1)^2+[根号(y-1)-1]^2+[根号(z-2)-1]^2=0所以根号x-1=根号(y-1)-1=根号(z-2)-1=0x=1y=2z=3
