let√x = sinudx = 2sinu.cosu du∫ arcsin√x /√(1-x) dx=∫ [u/cosu] [2sinu.cosu du]=2∫ usinu du=-2∫ u dcosu=-2ucosu +2∫ cosu du=-2ucosu +2sinu +C=-2(arcsin√x) .√(1-x) +2√x +C
