X-5/X-(10/X+1)=1x-5/x-10/x-1=1x的平方-2X-15=0X=-3, 或 X=5
解:方程两边同乘x得 x^2-5-10-x=x 整理得:x^2-2x-15=0 所以(x-5)(x+3)=0 解得:x=5或者x=-3
去括号x-5/x-10/x-1=1两边同乘xx^2-5-10-x=x移项、合并x^2-2x-15=0解得x1=5,x2=-3