构造下凸函f(s,t)=s^4/t(1-t^2),则f(x,y)+f(y,z)+f(z,x)≥3f[(x+y+z)/3,(x+y+z)/3] =3f(1/3,1/3),∴x^4/y(1-y^2)+y^4/z(1-z^2)+z^4/x(1-x^2)≥3×[(1/3)^4/((1/3)×(1-(1/3)^2)]=1/8,故所求最小值为: 1/8。