求大神帮忙解答高数积分题

2025-05-19 13:02:15
推荐回答(1个)
回答1:

=x√(x²-a²)-∫x²/√(x²-a²)dx
=x√(x²-a²)-∫√(x²-a²)+a²/√(x²-a²)dx
=x√(x²-a²)-a²ln(x+√(x²-a²))-∫√(x²-a²)dx
=(x√(x²-a²)-a²ln|x+√(x²-a²)|)/2+C