已知圆C:x2+y2-2x-4y+m=0.(1)求m的取值范围.(2)当m=4时...

2025-05-19 07:57:10
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回答1:

解:(1)圆C:x2+y2-2x-4y+m=0

圆C:(x-1)2+(y-2)2
=5-m,∴m<5.
(2)当m=4时,∴圆C:(x-1)2+(y-2)2
=1,
圆心C:(1,2),半径r=1,
∵CM⊥CN,∴弦心距d=22r,即
|1+2a-4|1+a2=22,化简:7a2-24a+17=0,
求得a=1,或
a=177.