(π-3)^0

(π-3)^0-(1/2)^-1+(2/3)^2008*(-1.5)^2009
2025-05-15 02:01:46
推荐回答(1个)
回答1:

原式=1-(1/2)^-1+(2/3)^2008*(-1.5)^2009
=1-2+(-3/2)(2/3)^2008*(-3/2)^2008
=-1+(-3/2)(2/3)*(-3/2)^2008
=-1+(-3/2)(-1)^2008
=-1+(-3/2)
=-5/2