(1)lim(x->-1-) e^(1/x^2) . arctan[(x^2+x+1)/(x+1)(x-2)]=e.lim(x->-1-) arctan[(x^2+x+1)/(x+1)(x-2)]=e .(π/2)lim(x->-1-) [(x^2+x+1)/(x+1)(x-2)] ->+∞>0母>0
