∫(e^(2t)cost)dt=(1/2)∫costd(e^(2t))=(1/2)coste^(2t)+(1/2)∫e^(2t)sintdt=(1/2)coste^(2t)+(1/4)∫sintd(e^(2t))=(1/2)coste^(2t)+(1/4)sinte^(2t)-(1/4)∫e^(2t)costdt移项,两边同时乘以4/5,得∫e^(2t)costdt=(2/5)coste^(2t)+(1/5)sint*e^(2t)+C带入积分区间=(1/5)e^π-(2/5)