两正数不互为相反数，所以/a+b+1/与(a-b+1)^2都是0a+b+1=0a-b+1=0解得：a=-1,b=0
互为相反数即/a+b+1/=-(a-b+1)^2移项/a+b+1/+(a-b+1)^2=0/a+b+1/>=0,(a-b+1)^2>=0,两个零相加才等于0即/a+b+1/=0(a-b+1)^2=0连理解的a=-1b=0
