若x^2+xy=3,xy+y^2=-2,则2x^2-xy-3y^2的值为多少

若x^2+xy=3,xy+y^2=-2,则2x^2-xy-3y^2的值为多少?详细步骤
2025-05-15 06:32:29
推荐回答(2个)
回答1:

x² + xy = 3
两边同时乘以 2 得:
2x² + 2xy = 6 ①

xy + y² = -2
两边同时乘以 3 得:
3xy + 3y² = -6 ②

① - ② 得:
2x² - xy - 3y² = 12

回答2:

x2 + xy = 3
两边同时乘以 2 得:
2x2 + 2xy = 6 ①

xy + y2 = -2
两边同时乘以 3 得:
3xy + 3y2 = -6 ②

① - ② 得:
2x2 - xy - 3y2 = 12