先化简再求值:(I) 求3x2y?[5xy2+2(x2y?12)+x2y]+6xy2的值,其中x=-2,y=12(II) 已知x,y,z满足:(

2025-05-11 00:58:23
推荐回答(1个)
回答1:

(1)原式=3x2y-5xy2-2x2y+1-x2y+6xy2=xy2+1,
当x=-2,y=

1
2
时,原式=-2×(
1
2
2+1=-
1
2
+1=
1
2

(2)∵|x-2|+(y+3)2=0,z是最大的负整数,
∴x=2,y=-3,z=-1,
而原式=2x2y+2xyz-3x2y+3xyz-4x2y=5xyz-5x2y,
当x=2,y=-3,y=-1时,原式=5×2×(-3)×(-1)-5×22×(-3)=90.