设g(x)=lnx+1-x,g'(x)=1/x-1,g(x)的极大值也是最大值是g(1)=0g(x)=lnx+1-x<=0,(lnx+1)/x<=1(x=1时取等号),(lnx+1)/x的最大值是1f(x)≤kx,k>=(lnx+1)/x等价于k>=1
k的取值范围为:k>=1http://zhidao.baidu.com/question/235493962.html?an=0&si=1