(1)1mL pH=1的H2SO4溶液加水稀释到100mL,c(H+)由0.1mol/L变为0.001mol/L,则pH=-lg0.001=3,
故答案为:3;
(2)常温下,0.01mol?L-1的NaOH溶液的pH为12,而某温度时测得0.01mol?L-1的NaOH溶液的pH为11,则KW=0.01×10-11=1.0×10-13,温度高于25℃,
故答案为:1.0×10-13;
(3)pH=5的H2SO4的溶液中由水电离出的H+浓度为c1=
=10-9mol/L,pH=9的Ba(OH)2溶液中由水电离出的H+浓度为c2=10-9mol/L,则10?14
10?5
=1,故答案为:1;c1 c2
(4)若所得混合溶液呈中性,aL×0.1mol/L=bL×0.001mol/L,解得a:b=1:100;若所得混合溶液pH=12,则碱过量,所以
=0.01mol/L,解得a:b=11:90,a×0.1?b×0.001 a+b
故答案为:1:100;11:90.