(5x^2-4y^2)(-5x^2+4y^2)

值是多少啊?
2025-05-18 08:48:51
推荐回答(2个)
回答1:

(5x^2-4y^2)(-5x^2+4y^2)
=-(5x²-4y²)²
=-(25x^4-40x²y²+16y^4)
=-25x^4+40x²y²-16y^4

回答2:

(5x^2-4y^2)(-5x^2+4y^2)
=-﹙5x^2-4y^2﹚﹙5x^2-4y^2﹚
=-﹙25x^4-40x^2y^2+16y^4﹚
=-25x^4+40x^2y^2-16y^4