方程(x-1)(x-1)(x+1)=1⼀2的解法

2025-05-18 14:05:07
推荐回答(2个)
回答1:

3(x+1)-1/3(x-1)=2(x-1)-1/2(x+1)
3(x+1)+(x+1)/2=2(x-1)+(x-1)/3
7(x+1)/2=7(x-1)/3
(x+1)/2=(x-1)/3
3(x+1)=2(x-1)

是5-(2x+3)-3/4(x-2)=2(x-2)-1/2(2x+3)吗?是的话
(2x+3)-(2x+3)/2=5-2(x-2)-3(x-2)/4
(2x+3)/2=5-11(x-2)/4
2(2x+3)=20-11(x-2)

回答2:

(x-1)(x²-1)=1/2
x³-x²-x+0.5=0
x1≈0.4030
x2≈1.4516
x3≈-.8546