三角函数取值范围的一道题,哪个大神帮帮忙

2025-05-18 08:00:18
推荐回答(1个)
回答1:

f(x)=1/2sin2x+(1-cos2x)/2
=1/2sin2x-1/2cos2x+1/2
=√2/2(sin2x*√2/2-cos2x*√2/2)+1/2
=√2/2sin(2x-π/4)+1/2
最小正周期T=2π/2=π

2kπ-π/2<=2x-π/4<=2kπ+π/2
kπ-π/8<=x<=kπ+3π/8
单调递增区间 【kπ-π/8,kπ+3π/8】 k∈Z