首先求定义域x+1>0且2x-1>0x>-1且x>1/2取交集,得到x>1/2因为lga在定义域上是增函数lg(X+1)≤2lg(2X-1)lg(x+1)<=lg(2x-1)^2x+1<=(2x-1)^24x^2-4x+1>=x+14x^2>=5xx<=0或x>=5/4与定义域取交集,最后得到x>=5/4