1≤|2x-3|≤5化为两个不等式|2x-3|》1 => 2x-3》1，2x-3《-1 => x》2，x《1 ①|2x-3|≤5 => -5《2x-3《5 => -1《x《4 ②由①②取交集得不等式的解集为{x|-1《x《1,2《x《4}
2x-3>=12x-3<=-1x<=1或x>=2-5<=(2x-3)<=5-1<=x<=4答案：[-1,1]并[2,4]
