解：（1+z）/(1-z)=i1+z=i(1-z)1+z=i-izz+iz=i-1z(1+i)=i-1z=(i-1)/(1+i)z=(i-1)(1-i)/(1+i)(1-i)z=(i-i^2-1+i)/(1-i^2)z=(2i-(-1)-1)/(1-i^2)z=(2i+1-1)/(1-(-1))z=2i/2z=i答：z=i.
