这道数学题怎么做,11题计算。1-4题怎么做?

2025-05-16 04:53:52
推荐回答(2个)
回答1:

望采纳

回答2:

(1)原式=a²b^6 * (-b³ /a^6) * (-a^4/b^4)=(b^9/a^4)*(a^4/b^4)=b^5

(2)原式=-(a²b²/8)*(4b²/3a)*(9b^4/4a²)=-(ab^4/6)*(9b^4/4a²)=-9b^8/4

(3)原式=-x(x-y)*[xy/(x-y)²]*[(x-y)/x²]=-[x²y/(x-y)]*[(x-y)/x²]=-y

(4)原式=[x²(x-3)/(x-3)(x-2)]*[(x+3)(x-1)/x(x+3)(x-3)]*[(x-2)(x-6)/2x]

=[x²/(x-2)] * [(x-1)/x(x-3)] * [(x-2)(x-6)/2x]

=(x-1)(x-6)/2(x-3)