let
u= y/x
du/dx = (xy' - y)/x^2
x.du/dx = y' - y/x
y' = u + x.du/dx
/
xy' - xsin(y/x) -y =0
y' - sin(y/x) -(y/x) =0
u + x.du/dx - sinu - u = 0
x.du/dx = sinu
∫cscu du =∫dx/x
ln|cscu- cotu | = ln|x| + C'
cscu- cotu = Cx
csc(y/x) - cot(y/x) = Cx
内容全部来源于网络收集，如有侵权，请联系网站删除：QQ：24596024