x-2/x-1÷(x+1)-3/x-1)=x-2/(x-1)(x+1)-3(x+1)/(x-1)(x+1)=(x-2-3x-3)/x²-1=2x+5/1-X²代入√3-2得[2(√3-2)+5]/[1-(√3-2)²]=(2√3+1)/[1-(3-4√3+4)]=(2√3+1)/(4√3-6)
