V = ∫<0, 2>dx∫<0, 2-x> (6-3x-2y)dy= ∫<0, 2>dx[(6-3x)y-y^2]<0, 2-x>= ∫<0, 2>[(6-3x)(2-x)-(2-x)^2]dx= ∫<0, 2>(2x^2-10x+8)dx= [(2/3)x^3-5x^2+8x]<0, 2> = 4/3
